(4y+7)^2=4(4y+7)+6

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Solution for (4y+7)^2=4(4y+7)+6 equation: 



(4y+7)^2=4(4y+7)+6

We move all terms to the left:

(4y+7)^2-(4(4y+7)+6)=0



We calculate terms in parentheses: -(4(4y+7)+6), so:

4(4y+7)+6

We multiply parentheses

16y+28+6

We add all the numbers together, and all the variables

16y+34

Back to the equation:

-(16y+34)



We get rid of parentheses

(4y+7)^2-16y-34=0

We add all the numbers together, and all the variables

-16y+(4y+7)^2-34=0

We move all terms containing y to the left, all other terms to the right

-16y+(4y+7)^2=34

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